Draw Trees With Order Type Traversal

Tree Traversal - inorder, preorder and postorder

In this tutorial, you will learn about different tree traversal techniques. Also, you will find working examples of different tree traversal methods in C, C++, Java and Python.

Traversing a tree means visiting every node in the tree. You might, for instance, want to add all the values in the tree or find the largest one. For all these operations, you will need to visit each node of the tree.

Linear data structures like arrays, stacks, queues, and linked list have only one way to read the data. But a hierarchical data structure like a tree can be traversed in different ways.

Tree traversal

Let's think about how we can read the elements of the tree in the image shown above.

Starting from top, Left to right

            1 -> 12 -> 5 -> 6 -> 9          

Starting from bottom, Left to right

            5 -> 6 -> 12 -> 9 -> 1          

Although this process is somewhat easy, it doesn't respect the hierarchy of the tree, only the depth of the nodes.

Instead, we use traversal methods that take into account the basic structure of a tree i.e.

            struct node {     int data;     struct node* left;     struct node* right; }          

The struct node pointed to by left and right might have other left and right children so we should think of them as sub-trees instead of sub-nodes.

According to this structure, every tree is a combination of

• A node carrying data
• Two subtrees

Left and Right Subtree

Remember that our goal is to visit each node, so we need to visit all the nodes in the subtree, visit the root node and visit all the nodes in the right subtree as well.

Depending on the order in which we do this, there can be three types of traversal.

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Inorder traversal

1. First, visit all the nodes in the left subtree
2. Then the root node
3. Visit all the nodes in the right subtree

            inorder(root->left) display(root->data) inorder(root->right)          

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Preorder traversal

1. Visit root node
2. Visit all the nodes in the left subtree
3. Visit all the nodes in the right subtree

            display(root->data) preorder(root->left) preorder(root->right)          

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Postorder traversal

1. Visit all the nodes in the left subtree
2. Visit all the nodes in the right subtree
3. Visit the root node

            postorder(root->left) postorder(root->right) display(root->data)          

Let's visualize in-order traversal. We start from the root node.

Left and Right Subtree

We traverse the left subtree first. We also need to remember to visit the root node and the right subtree when this tree is done.

Let's put all this in a stack so that we remember.

Stack

Now we traverse to the subtree pointed on the TOP of the stack.

Again, we follow the same rule of inorder

Left subtree -> root -> right subtree

After traversing the left subtree, we are left with

Final Stack

Since the node "5" doesn't have any subtrees, we print it directly. After that we print its parent "12" and then the right child "6".

Putting everything on a stack was helpful because now that the left-subtree of the root node has been traversed, we can print it and go to the right subtree.

After going through all the elements, we get the inorder traversal as

            5 -> 12 -> 6 -> 1 -> 9          

We don't have to create the stack ourselves because recursion maintains the correct order for us.

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Python, Java and C/C++ Examples

                # Tree traversal in Python   class Node:     def __init__(self, item):         self.left = None         self.right = None         self.val = item   def inorder(root):      if root:         # Traverse left         inorder(root.left)         # Traverse root         print(str(root.val) + "->", end='')         # Traverse right         inorder(root.right)   def postorder(root):      if root:         # Traverse left         postorder(root.left)         # Traverse right         postorder(root.right)         # Traverse root         print(str(root.val) + "->", end='')   def preorder(root):      if root:         # Traverse root         print(str(root.val) + "->", end='')         # Traverse left         preorder(root.left)         # Traverse right         preorder(root.right)   root = Node(1) root.left = Node(2) root.right = Node(3) root.left.left = Node(4) root.left.right = Node(5)  print("Inorder traversal ") inorder(root)  print("\nPreorder traversal ") preorder(root)  print("\nPostorder traversal ") postorder(root)              

                // Tree traversal in Java  class Node {   int item;   Node left, right;    public Node(int key) {   item = key;   left = right = null;   } }  class BinaryTree {   // Root of Binary Tree   Node root;    BinaryTree() {   root = null;   }    void postorder(Node node) {   if (node == null)     return;    // Traverse left   postorder(node.left);   // Traverse right   postorder(node.right);   // Traverse root   System.out.print(node.item + "->");   }    void inorder(Node node) {   if (node == null)     return;    // Traverse left   inorder(node.left);   // Traverse root   System.out.print(node.item + "->");   // Traverse right   inorder(node.right);   }    void preorder(Node node) {   if (node == null)     return;    // Traverse root   System.out.print(node.item + "->");   // Traverse left   preorder(node.left);   // Traverse right   preorder(node.right);   }    public static void main(String[] args) {   BinaryTree tree = new BinaryTree();   tree.root = new Node(1);   tree.root.left = new Node(12);   tree.root.right = new Node(9);   tree.root.left.left = new Node(5);   tree.root.left.right = new Node(6);    System.out.println("Inorder traversal");   tree.inorder(tree.root);    System.out.println("\nPreorder traversal ");   tree.preorder(tree.root);    System.out.println("\nPostorder traversal");   tree.postorder(tree.root);   } }              

                // Tree traversal in C  #include <stdio.h> #include <stdlib.h>  struct node {   int item;   struct node* left;   struct node* right; };  // Inorder traversal void inorderTraversal(struct node* root) {   if (root == NULL) return;   inorderTraversal(root->left);   printf("%d ->", root->item);   inorderTraversal(root->right); }  // preorderTraversal traversal void preorderTraversal(struct node* root) {   if (root == NULL) return;   printf("%d ->", root->item);   preorderTraversal(root->left);   preorderTraversal(root->right); }  // postorderTraversal traversal void postorderTraversal(struct node* root) {   if (root == NULL) return;   postorderTraversal(root->left);   postorderTraversal(root->right);   printf("%d ->", root->item); }  // Create a new Node struct node* createNode(value) {   struct node* newNode = malloc(sizeof(struct node));   newNode->item = value;   newNode->left = NULL;   newNode->right = NULL;    return newNode; }  // Insert on the left of the node struct node* insertLeft(struct node* root, int value) {   root->left = createNode(value);   return root->left; }  // Insert on the right of the node struct node* insertRight(struct node* root, int value) {   root->right = createNode(value);   return root->right; }  int main() {   struct node* root = createNode(1);   insertLeft(root, 12);   insertRight(root, 9);    insertLeft(root->left, 5);   insertRight(root->left, 6);    printf("Inorder traversal \n");   inorderTraversal(root);    printf("\nPreorder traversal \n");   preorderTraversal(root);    printf("\nPostorder traversal \n");   postorderTraversal(root); }              

                // Tree traversal in C++  #include <iostream> using namespace std;  struct Node {   int data;   struct Node *left, *right;   Node(int data) {     this->data = data;     left = right = NULL;   } };  // Preorder traversal void preorderTraversal(struct Node* node) {   if (node == NULL)     return;    cout << node->data << "->";   preorderTraversal(node->left);   preorderTraversal(node->right); }  // Postorder traversal void postorderTraversal(struct Node* node) {   if (node == NULL)     return;    postorderTraversal(node->left);   postorderTraversal(node->right);   cout << node->data << "->"; }  // Inorder traversal void inorderTraversal(struct Node* node) {   if (node == NULL)     return;    inorderTraversal(node->left);   cout << node->data << "->";   inorderTraversal(node->right); }  int main() {   struct Node* root = new Node(1);   root->left = new Node(12);   root->right = new Node(9);   root->left->left = new Node(5);   root->left->right = new Node(6);    cout << "Inorder traversal ";   inorderTraversal(root);    cout << "\nPreorder traversal ";   preorderTraversal(root);    cout << "\nPostorder traversal ";   postorderTraversal(root);              

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Source: https://www.programiz.com/dsa/tree-traversal

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